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x^2-6.2x+6=0
a = 1; b = -6.2; c = +6;
Δ = b2-4ac
Δ = -6.22-4·1·6
Δ = 14.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.2)-\sqrt{14.44}}{2*1}=\frac{6.2-\sqrt{14.44}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.2)+\sqrt{14.44}}{2*1}=\frac{6.2+\sqrt{14.44}}{2} $
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